tf.sets.union

TensorFlow 1 version View source on GitHub

Compute set union of elements in last dimension of a and b.

tf.sets.union(
    a, b, validate_indices=True
)

All but the last dimension of a and b must match.

Example:

  import tensorflow as tf
  import collections

  # [[{1, 2}, {3}], [{4}, {5, 6}]]
  a = collections.OrderedDict([
      ((0, 0, 0), 1),
      ((0, 0, 1), 2),
      ((0, 1, 0), 3),
      ((1, 0, 0), 4),
      ((1, 1, 0), 5),
      ((1, 1, 1), 6),
  ])
  a = tf.SparseTensor(list(a.keys()), list(a.values()), dense_shape=[2, 2, 2])

  # [[{1, 3}, {2}], [{4, 5}, {5, 6, 7, 8}]]
  b = collections.OrderedDict([
      ((0, 0, 0), 1),
      ((0, 0, 1), 3),
      ((0, 1, 0), 2),
      ((1, 0, 0), 4),
      ((1, 0, 1), 5),
      ((1, 1, 0), 5),
      ((1, 1, 1), 6),
      ((1, 1, 2), 7),
      ((1, 1, 3), 8),
  ])
  b = tf.SparseTensor(list(b.keys()), list(b.values()), dense_shape=[2, 2, 4])

  # `set_union` is applied to each aligned pair of sets.
  tf.sets.union(a, b)

  # The result will be a equivalent to either of:
  #
  # np.array([[{1, 2, 3}, {2, 3}], [{4, 5}, {5, 6, 7, 8}]])
  #
  # collections.OrderedDict([
  #     ((0, 0, 0), 1),
  #     ((0, 0, 1), 2),
  #     ((0, 0, 2), 3),
  #     ((0, 1, 0), 2),
  #     ((0, 1, 1), 3),
  #     ((1, 0, 0), 4),
  #     ((1, 0, 1), 5),
  #     ((1, 1, 0), 5),
  #     ((1, 1, 1), 6),
  #     ((1, 1, 2), 7),
  #     ((1, 1, 3), 8),
  # ])

a Tensor or SparseTensor of the same type as b. If sparse, indices must be sorted in row-major order.
b Tensor or SparseTensor of the same type as a. If sparse, indices must be sorted in row-major order.
validate_indices Whether to validate the order and range of sparse indices in a and b.

A SparseTensor whose shape is the same rank as a and b, and all but the last dimension the same. Elements along the last dimension contain the unions.