tf.math.reduce_max

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Computes tf.math.maximum of elements across dimensions of a tensor.

tf.math.reduce_max(
    input_tensor, axis=None, keepdims=False, name=None
)

This is the reduction operation for the elementwise tf.math.maximum op.

Reduces input_tensor along the dimensions given in axis. Unless keepdims is true, the rank of the tensor is reduced by 1 for each of the entries in axis, which must be unique. If keepdims is true, the reduced dimensions are retained with length 1.

If axis is None, all dimensions are reduced, and a tensor with a single element is returned.

>>> x = tf.constant([5, 1, 2, 4])
>>> tf.reduce_max(x)
<tf.Tensor: shape=(), dtype=int32, numpy=5>
>>> x = tf.constant([-5, -1, -2, -4])
>>> tf.reduce_max(x)
<tf.Tensor: shape=(), dtype=int32, numpy=-1>
>>> x = tf.constant([4, float('nan')])
>>> tf.reduce_max(x)
<tf.Tensor: shape=(), dtype=float32, numpy=nan>
>>> x = tf.constant([float('nan'), float('nan')])
>>> tf.reduce_max(x)
<tf.Tensor: shape=(), dtype=float32, numpy=nan>
>>> x = tf.constant([float('-inf'), float('inf')])
>>> tf.reduce_max(x)
<tf.Tensor: shape=(), dtype=float32, numpy=inf>

See the numpy docs for np.amax and np.nanmax behavior.